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  1. import re
  2. text = r'Codes like 123/456\n \n123/3456 \n123/23456\n etc are correct \n333.3333/333\n'
  3. print( re.findall(r'(?<!\S(?<!\\n))\d{3}[./]\d{3,6}(?:/\d{3})?(?!(?!\\n)\S)', text) )
  4.  
Success #stdin #stdout 0.02s 9664KB
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Standard input is empty
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['123/456', '123/3456', '123/23456', '333.3333/333']
https://ideone.com/m6GbGb
language:
Python 3 (python  3.9.5)
created:
3 years ago
visibility:
secret

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