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  1. #include <cmath>
  2. #include <iostream>
  3. using namespace std;
  4. int main() {
  5. 	long long n;
  6. 	cin >> n, n = abs(n);
  7. 	int s = 0, l = n ? log10(n) : 1;
  8. 	do
  9. 		s += n % 10 * (l-- % 2);
  10. 	while(n /= 10);
  11. 	cout << s << endl;
  12. }
Success #stdin #stdout 0.01s 5288KB
comments (?)
stdin 
-1234567
stdout 
12
https://ideone.com/YtvXow
Сумму цифр с чётными номерами в исходном числе.

https://o...content-available-to-author-only...l.ru/question/224533929
language:
C++ (gcc 8.3)
created:
4 years ago
visibility:
public

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