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  1. #include <stdio.h>
  2. int main(void)
  3. {
  4.     int   i, n;
  5.     long  p=1; 
  6.     printf("Please enter n:");
  7.     scanf("%d", &n);
  8.     for (i=1; i<=n; i++)
  9.     {
  10.          p=p*i;               
  11.     }
  12.     printf("%d! = %ld\n", n, p);     /* 以长整型格式输出n的阶乘值 */
  13.     return 0;
  14. }
  15.  
Success #stdin #stdout 0s 5320KB
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stdin
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3
stdout
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Please enter n:3! = 6
https://ideone.com/XUbn0o
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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