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  1. #include <stdio.h>
  2. double power(double x,int n){
  3.     double p=1;
  4.     int i;
  5.     for(i=1;i<=n;i++)
  6.     p=p*x;
  7.     return p;
  8. }
  9. int main(void) {
  10. 	double x;
  11.     int n;
  12.     int m;
  13.     scanf("%f%d\n",&x,&n);
  14.     m=power(x,n);
  15.     printf("%f的%d次方是：%f",x,n,m);
  16. 	return 0;
  17. }
  18.  
Success #stdin #stdout 0s 5356KB
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stdin
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3.0 2
stdout
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0.000000的2次方是：0.000000
https://ideone.com/Ipt0Gk
language:
C (gcc 8.3)
created:
4 hours ago
visibility:
public

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