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  1. import re
  2. s = '# 53421.0 67778.0000002 0.3673987009 1 1517.750 88.370 512 7 1 J1745-3040'
  3. print( re.findall(r'\b\w(?:\S*\w)?\b', s) )
Success #stdin #stdout 0.03s 9480KB
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['53421.0', '67778.0000002', '0.3673987009', '1', '1517.750', '88.370', '512', '7', '1', 'J1745-3040']
https://ideone.com/BVQujP
language:
Python 3 (python  3.12)
created:
4 years ago
visibility:
secret

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