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  1. x <- "123456789
  2. kfasdf  3456789asdf
  3. a        1
  4.  
  5. 12345 789
  6. 1       9
  7. a     678a"
  8.     regmatches(x, gregexpr("(?<![\\d\\h])(?>\\d|(?<!\\d)\\h){8}\\d", x, perl=TRUE))
Success #stdin #stdout 0.24s 39224KB
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[[1]]
[1] "123456789" "  3456789" "        1"
https://ideone.com/sdRSch
language:
R (R 3.5.2)
created:
5 years ago
visibility:
public

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