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#include <stdio.h>
 
int main(void) {
	// your code goes here
	return 0;
}
#include<stdio.h>
void main()
{
 
    int a,b;
    char ch;
    printf("press\n 1.addition \n 2.substraction\n 3.multiplication \n 4.division\n");
    printf("\nenter choice:");
    scanf("%c",&ch);
    printf("\nenter integer:");
    scanf("%d",&a);
    printf("\nenter integer:");
    scanf("%d",&b);
 
    switch(ch)
    {
    case '+':
        printf("%d+%d=%d",a,b,a+b);
        break;
    case '-':
        printf("%d-%d=%d",a,b,a-b);
        break;
    case '*':
        printf("%d*%d=%d",a,b,a*b);
        break;
    case '/':
        printf("%d/%d=%d",a,b,a/b);
        break;
    default:
        printf("error");
        break;
    }
}
 

prog.c:8:6: warning: return type of ‘main’ is not ‘int’ [-Wmain]
 void main()
      ^~~~
prog.c:8:6: error: conflicting types for ‘main’
prog.c:3:5: note: previous definition of ‘main’ was here
 int main(void) {
     ^~~~
prog.c: In function ‘main’:
prog.c:15:5: warning: ignoring return value of ‘scanf’, declared with attribute warn_unused_result [-Wunused-result]
     scanf("%c",&ch);
     ^~~~~~~~~~~~~~~
prog.c:17:5: warning: ignoring return value of ‘scanf’, declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d",&a);
     ^~~~~~~~~~~~~~
prog.c:19:5: warning: ignoring return value of ‘scanf’, declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d",&b);
     ^~~~~~~~~~~~~~

Standard output is empty