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  1. #include <bits/stdc++.h>
  2. #define ll long long int
  3. #define N 101
  4. #define mod 1000000007
  5. using namespace std;
  6.  
  7. ll a[N][N] = {0},I[N][N];
  8. void mul(ll A[][N], ll B[][N], ll dim)
  9. {
  10.     ll res[dim+1][dim+1];
  11.     for (ll i = 0 ; i < dim; i++)
  12.     {
  13.         for (ll j = 0 ; j < dim; j++)
  14.         {
  15.             res[i][j] = 0;
  16.             for (ll k = 0; k < dim; k++)
  17.             {
  18.                 res[i][j] = ((res[i][j]) + (A[i][k] * B[k][j])%mod ) % mod;
  19.             }
  20.         }
  21.     }
  22.  
  23.     for (ll i = 0 ; i < dim; i++)
  24.     {
  25.         for (ll j = 0; j < dim; j++)
  26.         {
  27.             A[i][j] = res[i][j];
  28.         }
  29.     }
  30. }
  31. void power(ll A[][N], ll dim, ll n)
  32. {
  33.     for (ll i = 0 ; i < dim; i++)
  34.     {
  35.         for(ll j = 0 ; j < dim;j++)
  36.         {
  37.             if (i == j)
  38.                 I[i][j] = 1;
  39.             else
  40.                 I[i][j] = 0;
  41.         }
  42.     }
  43.  
  44.     while(n > 0)
  45.     {
  46.         if(n % 2)
  47.         {
  48.             mul(I, A,dim);
  49.         }
  50.         mul(A,A,dim);
  51.         n /= 2;
  52.     }
  53.  
  54.     for (ll i = 0 ; i < dim; i++)
  55.         for (ll j = 0; j < dim; j++)
  56.             A[i][j] = I[i][j];
  57. }
  58. int main()
  59. {
  60.     ll n;
  61.     cin >> n;
  62.     for(ll i = 0;i < 6;i++)
  63.         a[i][5] = 1;
  64.     a[1][0] = 1;
  65.     a[2][1] = 1;
  66.     a[3][2] = 1;
  67.     a[4][3] = 1;
  68.     a[5][4] = 1;
  69.  
  70.     power(a, 6, n-1);
  71.     cout << 2 * a[1][0];
  72.     return 0;
  73. }
  74.  
Success #stdin #stdout 0s 4256KB
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1781709090
https://ideone.com/sE6Pgm
language:
C++14 (gcc 8.3)
created:
3 years ago
visibility:
public

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