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  1. from urllib import parse
  2. url = r'htt'+'p://link.ru/123-456/text789/1122-hi-90.html'
  3. print(parse.urlsplit(url).path.rsplit('/')[-1].split('-')[0])
Success #stdin #stdout 0.03s 9692KB
comments (?)
stdin 
Standard input is empty
stdout 
1122
https://ideone.com/rUvb6E
language:
Python 3 (python  3.12)
created:
4 years ago
visibility:
public

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