/* package whatever; // don't place package name! */
 
import java.util.*;
import java.lang.*;
import java.io.*;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
 
/* Name of the class has to be "Main" only if the class is public. */
class Ideone
{
	public static void main (String[] args) throws java.lang.Exception
	{
final String regex = "(?<=1.*\\[)\\w+(?=\\])";
        final String string = "I have a string line: 1aa[appleax]bb[appley]\n\n"
	 + "I want to capture both applex and appley via regex and if there are more - I want to capture them too. I want words between brackets.\n\n"
	 + "Here is a catch: I want to capture them only if they go after 1. If they go before 1 - I am not interested.\n\n"
	 + "I've tried these 2 approaches (below) but they either give me applex or appley (greedy/lazy). But I want all of them. Does anybody know what I can use?\n\n"
	 + "Approaches I've tried:\n\n"
	 + "Catches only applex: 1.*?\\[(\\w*)\\]\n"
	 + "Catches only appley: 1.*\\[(\\w*)\\]";
 
        final Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE);
        final Matcher matcher = pattern.matcher(string);
 
        while (matcher.find()) {
            System.out.println("Full match: " + matcher.group(0));
 
            for (int i = 1; i <= matcher.groupCount(); i++) {
                System.out.println("Group " + i + ": " + matcher.group(i));
            }
        }
	}
}

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