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  1. import re
  2.  
  3. pattern = r"^\d+\.[^\S\n]*(.*(?:\n(?!\d+\.).*)*)"
  4. s = ("1. foobar\n\n"
  5.      "2. foo\n\n"
  6.      "3. bar\ntest\n\n")
  7.  
  8. print([x.strip() for x in re.findall(pattern, s, re.M)])
Success #stdin #stdout 0.03s 9640KB
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stdin
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Standard input is empty
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['foobar', 'foo', 'bar\ntest']
https://ideone.com/pCdVtH
language:
Python 3 (python  3.12)
created:
1 year ago
visibility:
secret

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