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  1. s="\083\022\118\106\100\032\066\057\065\069\068\057\043"
  2. reinraus=1
  3. for i=1,#s do reinraus=reinraus..string.char((string.byte(s,i)+5*(i%3))%256) end;
  4. print(string.sub(reinraus,2))
Success #stdin #stdout 0.01s 5268KB
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Standard input is empty
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X von GCAJN90
https://ideone.com/otPHmb
language:
Lua (luac 5.3.3)
created:
39 days ago
visibility:
public

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