#include <iostream>
#include <cmath>
using namespace std;
int main() {
long long h1, m1, h2, m2, sum, sum1=0, sum2=0, res1=0, res2=0;
char a;
cin >> h1 >> a >> m1 >> h2 >> a >> m2;
sum1=h1*60+m1;
sum2=h2*60+m2;
sum=(1440+(sum2-sum1))%1440; //количество минут между 1 и 2 временем учитывая переход через полночь
sum2=sum1+sum;
double r;
r=(h1%12+m1/12.0+1);//12:00 и 00:00
res1=sum1*11/720+ceil((r-1)/r);
res2=sum2*11/720+1;
cout << res2-res1;
return 0;
}
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