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  1. def checku(a):
  2.     vc = [a[0], 1, 0, 0]
  3.     for v in a[1:]:
  4.         if v == vc[0]:
  5.             vc[1] += 1
  6.         else:
  7.             if vc[3] == 0 or v==vc[2]:
  8.                 vc[2] = v
  9.                 vc[3] += 1
  10.             else:
  11.                 return False
  12.         if vc[1] > 1 and vc[3] > 1:
  13.             return False
  14.     return vc[1]>0 and vc[3]>0
  15.  
  16.  
  17.  
  18.  
  19. print(checku([1, 1, 2, 1, 1]))
  20. print(checku([2, 1, 1, 1, 1]))
  21. print(checku([1, 1, 2, 5, 1, 1]))
  22. print(checku([1, 1, 1, 1, 1]))
  23. print(checku([1, 1, 2, 2, 1]))
  24.  
Success #stdin #stdout 0.02s 9112KB
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stdin
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Standard input is empty
stdout
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True
True
False
False
False
https://ideone.com/nvyKBe
language:
Python 3 (python  3.12)
created:
3 years ago
visibility:
public

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