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  1.  
  2. d1 = {1: "hui", 3: "pizda", 2: "vzxcv", 62634: "fsfs", 4231: "fasfscv"}
  3. d2 = {"vzxcv": "tri", "hui": "odin", "pizda": "dva"}
  4. res = {k:d2[v] if v in d2 else v for k, v in d1.items()}
  5. print(res)
Success #stdin #stdout 0.02s 9284KB
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{1: 'odin', 3: 'dva', 2: 'tri', 62634: 'fsfs', 4231: 'fasfscv'}
https://ideone.com/mD8Omb
language:
Python 3 (python  3.12)
created:
3 years ago
visibility:
secret

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