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  1. /*
  2.   Given two coordinates, Print the line equation.
  3.   Objective -> 
  4.             Given two coordinates (x1,y1) and (x2,y2), write a C program to construct a line equation that
  5.             passes through the given coordinates.
  6.             A(3,7) B(5,11)
  7.             A(2,2) B(4,12)_
  8.  */
  9. #include <stdio.h>
  10.  
  11. struct TPoint {
  12. 	 float x,
  13. 	       y;
  14. };
  15.  
  16. typedef struct TPoint Point;
  17.  
  18. void read(Point *P) {
  19.  
  20.      printf("Abs -> ");  
  21.      scanf("%f", &P->x);
  22.  
  23.      printf("Ord -> ");  
  24.      scanf("%f", &P->y);
  25. }
  26.  
  27. float computeSlope(Point A, Point B) {
  28.  
  29.       return (B.y - A.y) / (B.x - A.x);
  30. }
  31.  
  32. void createEquation(Point A, Point B) {
  33.  
  34.       float m, a, b;
  35.  
  36.       m = computeSlope(A, B);
  37.  
  38.       a = m;
  39.       b = A.y - m * A.x; 
  40.  
  41.       if(m == 0) printf("Line Equation  -> y = %.2f\n", A.y);
  42.  
  43.       else {  
  44.             if(b > 0) printf("Line Equation  -> y = %.2f * x + %.2f\n", a, b);
  45.  
  46.                 else 
  47.  
  48.                       printf("Line Equation  -> y = %.2f * x - %.2f\n", a, b*(-1));      
  49.            }       
  50. };            
  51.  
  52. int main() {
  53.  
  54. 	Point A, B;
  55.  
  56. 	read(&A);
  57. 	read(&B);
  58. 	createEquation(A, B);
  59.  
  60. 	return(0);
  61. }
Success #stdin #stdout 0s 4300KB
comments (?)
stdin 
2
2
4
12
stdout 
Abs -> Ord -> Abs -> Ord -> Line Equation  -> y = 5.00 * x - 8.00
https://ideone.com/lWQlRm
Line Equation. m = (y - y1) / (x - x1)
language:
C (gcc 8.3)
created:
4 years ago
visibility:
public

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