#include <iostream>
 
using namespace std;
 
class one{
    int a;
public:
    void get(int);
    virtual void show();
};
 
class two:public one
{
    int b;
public:
    void getb(int);
    void dis();
    void show() override;  
};
 
void one::get(int x)  //if i write void two::get(int x) here it gives error
{
    a = x;
}
 
void one::show()  //same goes for this function why can't i define it as `void two::show()`?
{
  cout << a << endl;
}
 
void two::show()  //no problem !!
{
  cout << "two's version" << endl;
}
 
int main()
{
    two ob;
    int x;
    cin >> x;
    ob.get( x );
    ob.show();
    ob.one::show(); 
    one *pob = &ob;  // a one pointer can point to a two object 
    pob->show();    // but this will invoke one::show()
}

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