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  1. #include <stdio.h>
  2.  
  3. int main(int argc, char **argv) {
  4.     if (argc == 1) {
  5.         char *foo[] = {"bar", "baz", "quux", NULL, "bingo"};
  6.         main(3, foo);
  7.     } else {
  8.         printf("argc is %d; argv[4] is \"%s\"\n", argc, argv[4]);
  9.     }
  10.     return 0;
  11. }
Success #stdin #stdout 0s 5532KB
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stdin
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Standard input is empty
stdout
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argc is 3; argv[4] is "bingo"
https://ideone.com/kvTpP9
argv[argc + 1]
language:
C (gcc 8.3)
created:
1 year ago
visibility:
secret

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