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  1. import re
  2. p = re.compile(r'(?m)(^block\s*\d+).*(?:\n(?!block\s*\d).*)*\battrib\s*b=(\w+)')
  3. s = "block 1\n    subblock 1.1\n        attrib a=a1\n    subblock 1.2\n        attrib b=b1\nblock 2\n    subblock 2.1\n        attrib a=a2\nblock 3\n    subblock 3.1\n        attrib a=a3\n    subblock 3.2\n        attrib b=b3"
  4. print(p.findall(s))
Success #stdin #stdout 0.01s 9016KB
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Standard input is empty
stdout
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[('block 1', 'b1'), ('block 3', 'b3')]
https://ideone.com/j9eb9a
language:
Python (cpython 2.7.16)
created:
8 years ago
visibility:
secret

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