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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4.     int n;
  5.     scanf("%d", &n);
  6.  
  7.     int arr[n];
  8.     printf(" %d \n", n);
  9.     for (int i = 0; i < n; i++) {
  10.         scanf("%d", &arr[i]);
  11.     }
  12.  
  13.     printf("\n");
  14.     for (int i = 0; i < n; i++) {
  15.         int num = arr[i];
  16.         int sum = 0;
  17.         while (num != 0) {
  18.             int digit = num % 10;
  19.             sum += digit;
  20.             num /= 10;
  21.         }
  22.         printf("sum of %d = %d\n", arr[i], sum);
  23.     }
  24.  
  25.     return 0;
  26. }
  27.  
Success #stdin #stdout 0.01s 5272KB
comments (?)
stdin
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5 
43 22 11 87 65
stdout
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 5 

sum of 43 = 7
sum of 22 = 4
sum of 11 = 2
sum of 87 = 15
sum of 65 = 11
https://ideone.com/ikTy4m
language:
C (gcc 8.3)
created:
16 days ago
visibility:
public

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