import re
pattern = r'(?<!\d)(?<!\d\.)\d{1,2}(?:\.\d{1,2})?(?!\.?\d)'
print(re.findall(pattern, '10 rew 14.03 ytr 123 dsffd 15.443 er', re.ASCII))
aW1wb3J0IHJlCnBhdHRlcm4gPSByJyg/PCFcZCkoPzwhXGRcLilcZHsxLDJ9KD86XC5cZHsxLDJ9KT8oPyFcLj9cZCknCnByaW50KHJlLmZpbmRhbGwocGF0dGVybiwgJzEwIHJldyAxNC4wMyB5dHIgMTIzIGRzZmZkIDE1LjQ0MyBlcicsIHJlLkFTQ0lJKSk=