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  1. import re
  2. pattern = r'(?<!\d)(?<!\d\.)\d{1,2}(?:\.\d{1,2})?(?!\.?\d)'
  3. print(re.findall(pattern, '10 rew 14.03 ytr 123 dsffd 15.443 er', re.ASCII))
Success #stdin #stdout 0.02s 9520KB
stdin
Standard input is empty
stdout
['10', '14.03']