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  1. #include <iostream>
  2. using namespace std;
  3.  
  4. int F[51] = {0, 1, 1, 2, 3};
  5.  
  6. int numberOfWays(int n) {
  7.    if(F[n]) {
  8.       return F[n];
  9.    } else {
  10.       F[n] = numberOfWays(n-2) + numberOfWays(n-3) + numberOfWays(n-4);
  11.    }
  12.    return F[n];
  13. }
  14.  
  15. int main() {
  16.    int n;
  17.    cin >> n;
  18.    cout << numberOfWays(n);
  19.    return 0;
  20. }
Success #stdin #stdout 0s 4544KB
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https://ideone.com/iV1Jrd
Заповнення смуги 3 x n #2
language:
C++ (gcc 8.3)
created:
3 years ago
visibility:
public

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