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  1. #include <stdio.h>
  2.  
  3. double calculate_x(int n) {
  4.     double sum = 0.0;
  5.     for (int i = 1; i <= n; i++) {
  6.         sum += 1.0 / (i * (i + 1));
  7.     }
  8.     return sum;
  9. }
  10.  
  11. int main() {
  12.     int n1 = 3;
  13.     int n2 = 10;
  14.  
  15.     printf("x(%d) = %.6f\n", n1, calculate_x(n1));
  16.     printf("x(%d) = %.6f\n", n2, calculate_x(n2));
  17.  
  18.     return 0;
  19. }
  20.  
Success #stdin #stdout 0.01s 5280KB
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stdin
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Standard input is empty
stdout
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x(3) = 0.750000
x(10) = 0.909091
https://ideone.com/iH2mal
language:
C (gcc 8.3)
created:
4 days ago
visibility:
public

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