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  1. import re
  2.  
  3. regex=r"^host-vpp1out .*(?:\r?\n[^\S\r\n]*L3 .*)*"
  4. test_str = ("VirtualFuncEthernet0/7/0.2001 (up):\n"
  5.             "  L3 1.1.2.2/24 ip4 table-id 8 fib-idx 2\n"
  6.             "  L3 2001:db8:0:1:1:1:2:2/112 ip6 table-id 8 fib-idx 1\n"
  7.             "VirtualFuncEthernet0/9/0 (dn):\n"
  8.             "host-vpp1out (up):\n"
  9.             "  L3 1.1.1.1/24\n"
  10.             "  L3 1.1.2.1/24\n"
  11.             "  L3 2001:db8:0:1:1:1:1:1/112\n"
  12.             "  L3 2001:db8:0:1:1:1:2:1/112\n"
  13.             "local0 (dn):\n"
  14.             "loop0 (up):\n"
  15.             "  L3 1.1.1.1/32 ip4 table-id 7 fib-idx 1")
  16.  
  17. match = re.search(regex, test_str, re.MULTILINE)
  18.  
  19. if match:
  20.     print(re.findall(r" L3 (\d[\d.:\/a-z]+)\/\d+", match.group()))
Success #stdin #stdout 0.02s 9520KB
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Standard input is empty
stdout
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['1.1.1.1', '1.1.2.1', '2001:db8:0:1:1:1:1:1', '2001:db8:0:1:1:1:2:1']
https://ideone.com/i0oGYw
language:
Python 3 (python  3.12)
created:
5 years ago
visibility:
public

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