#include <iostream>
using namespace std;
 
const int N = 1e3 + 5;
 
using Bignum = string;
 
int n;
Bignum f[N][N]; 
 
/*
Hàm này trả về tổng của 2 số nguyên lớn x và y
VD: sum("123", "456") = "579", 
    sum("999", "1") = "1000", 
    sum("999", "999") = "1998"
*/
Bignum sum(Bignum x, Bignum y) {
    // Các bạn cần điền phần này 
}
 
void Read() {
    cin >> n;
}
 
void Solve() {
    // f[i][j] là số cách phân tích j thành tổng các số nguyên dương từ 1 đến i
    // f[i][j] = f[i - 1][j] + f[i][j - i]
    // <=> f[i][j] = sum(f[i - 1][j], f[i][j - i])
}
 
int main () {
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
 
    Read();
    Solve();
}

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