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import re
 
regex = r"(?::[:;]|[^;\n])+"
str = "foo;bar:;baz::;one:two;::three::::;four;;five:::;six;:seven;::eight"
print(re.findall(regex, str))

Success #stdin #stdout 0.02s 9620KB

stdin

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Standard input is empty

stdout

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['foo', 'bar:;baz::', 'one:two', '::three::::', 'four', 'five:::;six', ':seven', '::eight']

https://ideone.com/h3gvRE

language:

Python 3 (python 3.12)

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