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  1. #!/bin/bash
  2.  
  3.  
  4. echo something 1989-07-23 something.jpg foo-2013-01-10-bar.csv wordsidon\'tcareabout_2004-09-14_otherthings.tif foofoobarbar_2010-07-16.gif | grep -Po '(?<=\D)\d{4}(.\d\d){2}(?=\D)'
  5.  
Success #stdin #stdout 0.02s 5312KB
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1989-07-23
2013-01-10
2004-09-14
2010-07-16
https://ideone.com/gq8pd7
language:
Bash (bash 5.0.3)
created:
10 years ago
visibility:
public

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