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  1. #include <stdio.h>
  2.  
  3. /* The function in 97 bytes. */
  4. int f(int n,int a[n][n],int*b){for(int i=0;i<n;i++)for(int j=0,k=n;j<n;j++)*b++=a[i][i%2?j:--k];}
  5.  
  6. int main(void) {
  7. 	/* N != 0. */
  8. 	#define N 4
  9.  
  10. 	/* Declaration of the input array. */
  11. 	#if N == 4
  12. 		int input[N][N] = {{4, 3, 2, 1}, {5, 6, 7, 8}, {12, 11, 10, 9}, {13, 14, 15, 16}};
  13. 	#elif N == 3
  14. 		int input[N][N] = {{3, 2, 1}, {4, 5, 6}, {9, 8, 7}};
  15. 	#elif N == 2
  16. 		int input[N][N] = {{2, 1}, {3, 4}};
  17. 	#elif N == 1
  18. 		int input[N][N] = {{1}};
  19. 	#endif
  20.  
  21. 	/* Declaration of the output array. */
  22. 	int output[N * N];
  23.  
  24. 	/* Process. */
  25. 	f(N, input, output);
  26.  
  27. 	/* Check the result. */
  28. 	for (size_t i = 0; i < N*N; i++)
  29. 		printf("%d ", output[i]);
  30. }
Success #stdin #stdout 0s 9424KB
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https://ideone.com/gkk7Di
Solution for StackOverflow's code golf.
language:
C (gcc 8.3)
created:
5 years ago
visibility:
public

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