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  1. #include<iostream>
  2. #include<cmath>
  3. using namespace std;
  4. typedef long long ll;
  5. ll x,n;
  6.  
  7. ll eq1(ll i){
  8.     return (x-i+1 + 2*n-3) / (2*n - 2);
  9. }
  10. ll eq2(ll i){
  11.     return (x - (2*n -1 - i) + 2*n - 3) / (2*n - 2);
  12. }
  13.  
  14. int main(){
  15.  
  16.     ll t;  cin>>t;
  17.     while(t--){
  18.         cin>>x>>n;
  19.  
  20.         if(n==1) cout<<x<<endl;
  21.         else {
  22.             cout<<eq1(1)<<" ";
  23.  
  24.             for(ll i=2;i<n;i++)
  25.                 cout<<eq1(i)+eq2(i)<<" ";
  26.  
  27.             cout<<eq1(n)<<endl;
  28.         }
  29.  
  30.     }
  31.  
  32.     return 0;
  33. }
Success #stdin #stdout 0s 4400KB
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stdin
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stdout
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2 2 1
https://ideone.com/fsbHgL
language:
C++ (gcc 8.3)
created:
6 years ago
visibility:
public

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