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  1. #include <stdio.h>
  2. int main(){
  3. long n;
  4. int count = 0;
  5. int m[10],i;
  6.  
  7. for( i = 2; i < 10 ; i++ )
  8. {
  9. n /= 10;
  10. ++count;
  11. m[i]=i;
  12. printf("m[%d]= %d\n",i,m[i]);
  13.  
  14. }
  15.  
  16. printf("Counting number of digits: %d", count);
  17. }
Success #stdin #stdout 0s 2168KB
stdin
Standard input is empty
stdout
m[2]= 2
m[3]= 3
m[4]= 4
m[5]= 5
m[6]= 6
m[7]= 7
m[8]= 8
m[9]= 9
Counting number of digits: 8