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  1. import re
  2.  
  3. pattern = r"\b([1-9](?:\s*[0-9]){3})\s?([A-Z])(?i:\2*)\s*([A-Z])(?i:\3*)\b"
  4. strings = [
  5.     "1 2 3 4 Alpha Bravo",
  6.     "1234 Alpha Bravo",
  7.     "1234A Bbbbbbbc",
  8.     "1234Aaa Bbb",
  9.     "1234Aa Bbb",
  10.     "1234A BbbbbBbb"
  11. ]
  12.  
  13. for s in strings:
  14.     print(re.findall(pattern, s))
Success #stdin #stdout 0.02s 9856KB
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Standard input is empty
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[]
[]
[]
[('1234', 'A', 'B')]
[('1234', 'A', 'B')]
[('1234', 'A', 'B')]
https://ideone.com/fLvPje
language:
Python 3 (python  3.12)
created:
4 years ago
visibility:
public

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