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  1. import re
  2.  
  3. pattern = r"https?://\S+|(\d+)"
  4. s = "4758 11b98https://w...content-available-to-author-only...w.website11/111"
  5.  
  6. print(''.join(re.findall(pattern, s)))
Success #stdin #stdout 0.03s 9232KB
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47581198
https://ideone.com/fJ5iRE
language:
Python 3 (python  3.12)
created:
4 years ago
visibility:
secret

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