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  1. #include <iostream>
  2. #include <cstdio>
  3. #include <cmath>
  4.  
  5. using namespace std;
  6.  
  7. int main(){
  8.  
  9.   cout.setf(ios::fixed);
  10.   cout.setf(ios::showpoint);
  11.   cout.precision(3);
  12.  
  13.   int i, terms;
  14.  
  15.   cout << "Enter the number of terms to approximate (or zero to quit):\n";
  16.   cin >> terms;
  17.  
  18.     while(1){
  19.  
  20.         if (terms == 0){
  21.           return 0;
  22.         }
  23.  
  24.             if (terms > 0){
  25.  
  26.             double partial = 0;
  27.  
  28.             for (i = 0; i < terms; i++)
  29.                 if (i % 2 == 0)
  30.                     partial -= (pow(-1,terms))/((2.0 * i) + 1);
  31.                 else
  32.                     partial += (pow(-1,terms))/((2.0 * i) + 1);
  33.  
  34.             double newPi = 4 * partial;
  35.  
  36.             cout << "The approximation is " << newPi << " using " << terms << " terms.\n";
  37.  
  38.           }
  39.  
  40.         cout << "Enter the number of terms to approximate (or zero to quit):\n";
  41.         cin >> terms;
  42.  
  43.     }
  44.  
  45.   return 0;
  46. }
Time limit exceeded #stdin #stdout 5s 3472KB
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Standard input is empty
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Enter the number of terms to approximate (or zero to quit):
https://ideone.com/en2U9d
language:
C++14 (gcc 8.3)
created:
7 years ago
visibility:
public

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