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  1. def checku(a):
  2.     c = 0
  3.     for v in a:
  4.         if c == 0:
  5.             m = v
  6.             c = 1
  7.         else:
  8.             c = c + (1 if m == v else -1)
  9.     return a.count(m) == len(a) - 1
  10.  
  11. print(checku([1, 2]))
  12. print(checku([1, 1, 2, 1, 1]))
  13. print(checku([2, 1, 1, 1, 1]))
  14. print(checku([1]))
  15. print(checku([1, 2, 3]))
  16. print(checku([1, 1, 2, 5, 1, 1]))
  17. print(checku([1, 1, 1, 1, 1]))
  18. print(checku([1, 1, 2, 2, 1]))
Success #stdin #stdout 0.03s 8928KB
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stdin
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Standard input is empty
stdout
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True
True
True
False
False
False
False
False
https://ideone.com/ej4Zwa
language:
Python 3 (python  3.9.5)
created:
2 years ago
visibility:
public

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