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  1. #include <iostream>
  2. #include <iterator>
  3. #include <numeric>
  4.  
  5.  
  6. int main() {
  7.    int const res = std::accumulate(
  8.                        std::istream_iterator<int> { std::cin }, std::istream_iterator<int> {},
  9.                        0,
  10.                        [] (int const y, int const x) { return 113 * (y + x) % 10000007; });  
  11.    std::cout << res << '\n';
  12. }
  13.  
Success #stdin #stdout 0s 4512KB
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stdin
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3 1 4 1 5 9
stdout
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8921379
https://ideone.com/dRKdGx
language:
C++ (gcc 8.3)
created:
6 years ago
visibility:
public

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