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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4. 	int a[30];
  5. 	int i;
  6. 	a[0]=2;
  7. 	a[1]= -1;
  8. 	for(i=2;i<30;i++){
  9. 		a[i]= -a[i-1]+a[i-2]+2;
  10. 		if(a[i]>5000){
  11. 			printf("%d",i);
  12. 			break;
  13. 		}
  14. 	}
  15. 	return 0;
  16. }
  17.  
Success #stdin #stdout 0s 5288KB
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https://ideone.com/cyCSlV
language:
C (gcc 8.3)
created:
13 hours ago
visibility:
public

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