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  1. #include<iostream>
  2. #include<string>
  3. #include<deque>
  4.  
  5. using namespace std;
  6.  
  7. int a[1000001], n;
  8. long long int ans = 0;
  9. string s;
  10. int k;
  11.  
  12. int bn_find_first_max_right(int l, int r, long long int x)
  13. {
  14. int vt = -1;
  15. while (l <= r)
  16. {
  17. int mid = (l + r) / 2;
  18. if (a[mid] == x)
  19. {
  20. vt = mid;
  21. l = mid + 1;
  22. }
  23. else if (a[mid] > x)
  24. r = mid - 1;
  25. else if (a[mid] < x)
  26. l = mid + 1;
  27. }
  28. return vt;
  29. }
  30. int bn_find_first_max_left(int l, int r, long long int x)
  31. {
  32. int vt = -1;
  33. while (l <= r)
  34. {
  35. int mid = (l + r) / 2;
  36. if (a[mid] == x)
  37. {
  38. vt = mid;
  39. r = mid - 1;
  40. }
  41. else if (a[mid] > x)
  42. r = mid - 1;
  43. else if (a[mid] < x)
  44. l = mid + 1;
  45. }
  46. return vt;
  47. }
  48.  
  49. void inp()
  50. {
  51. cin >> k;
  52. cin.ignore();
  53. getline(cin, s);
  54. n = s.size();
  55. s = 'x' + s;
  56. for (int i = 1; i <= n; i++)
  57. a[i] = a[i - 1] + (s[i] - '0');
  58.  
  59. }
  60. void xuli()
  61. {
  62. for(int i = 1; i <= n; i++)
  63. if (a[i] >= k)
  64. {
  65. int left = bn_find_first_max_left(0, i - 1, a[i] - k);
  66. int right = bn_find_first_max_right(0, i - 1, a[i] - k);
  67. if(left != - 1 && right != -1)
  68. ans += right - left + 1;
  69. }
  70. cout << ans;
  71. }
  72. int main()
  73. {
  74. inp();
  75. xuli();
  76. }
  77.  
Success #stdin #stdout 0.01s 5392KB
stdin
100
01010
stdout
Standard output is empty