#include <stdlib.h>
#include <stdio.h>
#include <math.h>
int main(void) {
int a, query, in , n;
int sum[query+1];
for (a = 1; a <= query; a++) {
sum[a] = 0;
int b[in+1];
for (n = 1; n <= in ; n++) {
b[n] = 1 + 7 * (n - 1) + 6 * (n - 1) * (n - 2) + (n - 1) * (n - 2) * (n - 3);
sum[a] = sum[a] + b[n];
}
}
for (a = 1; a <= query; a++) {
}
return 0;
}
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