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  1. #include <iostream>
  2. #include <algorithm> //для использования функции sort
  3. using namespace std;
  4.  
  5. int main()
  6. {
  7. 	const int lch = 256;
  8. 	int n;
  9. 	cin>>n;
  10.  
  11. 	char **p = new char* [n]; //Создаем массив p, где будем хранить пары символов.
  12.     for (int i = 0; i < n; i++)
  13.     {
  14.         p[i] = new char [2];
  15.     }
  16.  
  17.     for (int i = 0; i < n; i++)
  18.  	{
  19.  		cin >> p[i][1]>>p[i][2];
  20.  	}
  21.  
  22.  	int chars[lch];
  23.  	for (int i = 0; i<lch; i++)
  24.  	{
  25.  		chars[i] = -1;
  26.  	}
  27.  	int K = 0;
  28.  	for (int i = 0; i<n; i++)
  29.  	{
  30.  		if (chars [ p[i][1]] == -1)
  31.  			K++;
  32.  		if (chars [ p[i][2]] == -1)
  33.  			K++;
  34.  		chars [ p[i][1]] = 0;
  35.  		chars [ p[i][2]] = 0;
  36.  	}
  37.  
  38.  	bool change;
  39.  	char x, y;
  40.  	int M;
  41.  	for (int i = 0; i < n; i++)
  42.  	{
  43.  		change = false;
  44.  		for (int j = 0; j < n; j++)
  45.  		{
  46.  			x = p[j][1];
  47.  			y = p[j][2];
  48.  			M = max(chars[x] + 1, chars [y]);
  49.  			if (M > (K-1))
  50.  			{
  51.  				cout<<"Порядок противоречив";
  52.  				return 0;
  53.  			}
  54.  			if (chars[y] != M)
  55.  			{
  56.  				change = true;
  57.  			}
  58.  			chars[y] = M;
  59.  		}
  60.  		if (!change)
  61.  		{
  62.  			sort(chars, chars+lch);
  63.  			int previous = K;
  64.  			int i = lch-1;
  65.  			while (chars [i] > -1)
  66.  			{
  67.  				if (chars[i] == previous - 1)
  68.  				{
  69.  					previous--;
  70.  				}
  71.  				else
  72.  				{
  73.  					cout<<"порядок неполный";
  74.  					return 0;
  75.  				}
  76.  				i--;
  77.  			}
  78.  			cout<<"полный порядок";
  79.  			return 0;
  80.  		}
  81.  	}
  82. 	return 0;
  83. }
Success #stdin #stdout 0s 3476KB
comments (?)
stdin
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10
a 5
5 4
b 3
3 4
5 3
b 5
a b
4 *
* 0
4 0
stdout
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полный порядок
https://ideone.com/YfKgss
AL1
language:
C++14 (gcc 8.3)
created:
7 years ago
visibility:
public

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