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  1. def iter(x, f, lim=10):
  2.     for _ in range(lim):
  3.         yield x
  4.         x = f(x)
  5.  
  6. print(list(iter(1, lambda x: (2 * x) % 99)))
  7. print([(n := (lambda x: (2 * x) % 99)(n)) if i else (n := 1) for i in range(10)])
Success #stdin #stdout 0.13s 14180KB
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[1, 2, 4, 8, 16, 32, 64, 29, 58, 17]
[1, 2, 4, 8, 16, 32, 64, 29, 58, 17]
https://ideone.com/Ye25ek
language:
Python 3 (python  3.12)
created:
107 days ago
visibility:
secret

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