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  1. #include <math.h>
  2. #include <stdio.h>
  3.  
  4. int ipow(double base, double exp) {
  5.     double res = pow(base, exp);
  6.     return *(int*)((void*)&res);
  7. }
  8.  
  9. int main(void) {
  10.     for (int n = 1; n < 6; n++) {
  11. 	    double x = 20 * pow(2.0, ((1-n)/5.0));
  12. 	    double y = 20 * ipow(2.0, ((1-n)/5.0));
  13.         printf("n=%d, x=%f, y=%f\n", n, x, y);
  14.     }
  15. 	return 0;
  16. }
  17.  
Success #stdin #stdout 0s 4516KB
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stdin
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Standard input is empty
stdout
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n=1, x=20.000000, y=0.000000
n=2, x=17.411011, y=422418048.000000
n=3, x=15.157166, y=1240833840.000000
n=4, x=13.195079, y=-1971682192.000000
n=5, x=11.486984, y=-2036727536.000000
https://ideone.com/XvPWX6
int pow??
language:
C (gcc 8.3)
created:
5 years ago
visibility:
secret

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