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  1. hex = [0,1,2,3,4,5,6,7,8,9,"A","B","C","D","E","F"]
  2. n = int(input("Digite um núemro inteiro: "))
  3. r = []
  4. while n > 0:
  5.     r.append(hex[(n % 16)])
  6.     n = n // 16
  7. for i in range(len(r)-1,-1,-1):
  8.     print(r[i],end="")
Success #stdin #stdout 0.01s 27720KB
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Digite um núemro inteiro: 3CA8
https://ideone.com/XpQD9v
language:
Python 3 (python  3.9.5)
created:
6 years ago
visibility:
public

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