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  1. #include <stdio.h>
  2. void p1(int);
  3. void p2(int);
  4. char *dig[] = {"零","壹","貳","參","肆","伍","陸","柒","捌","玖"};
  5. char *fer[] = {"\0","十","百","仟","萬","十","百","仟","億"};
  6. int times=0;
  7. int main()
  8. {
  9. 	int n;
  10. 	printf("N = ");
  11. 	scanf("%d",&n);
  12. 	p1(n);
  13. 	printf("元\n");
  14. 	return 0;
  15. } 
  16. void p1(int n)
  17. {
  18. 	int prefix,curryDig;
  19. 	if( n < 10){
  20. 		printf("%s",dig[n]);
  21. 		p2(times);
  22. 	}
  23. 	else{		
  24. 		prefix = n / 10;
  25. 		times++;
  26. 		p1(prefix);
  27. 		times--;
  28. 		curryDig = n % 10;
  29. 		if(curryDig == 0){
  30. 			int count = 0;
  31. 			while( prefix % 10 == 0){
  32. 				count++;
  33. 				prefix /= 10; 
  34. 				times--;
  35. 				curryDig = prefix % 10;
  36. 			}
  37. 			if(times != 0)
  38. 				printf("%s",dig[0]);
  39. 		}
  40. 		else{
  41. 			printf("%s",dig[curryDig]);
  42. 			p2(times);
  43. 		}
  44. 		}
  45. }
  46. void p2(int times)
  47. {
  48. 	printf("%s",fer[times]);
  49. }
Success #stdin #stdout 0s 4572KB
comments (?)
stdin 
Standard input is empty
stdout 
N = 零元
https://ideone.com/XnET5L
language:
C (gcc 8.3)
created:
5 years ago
visibility:
public

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