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  1.  
  2. int main() {
  3.     int number;
  4.     printf("请输入一个不多于五位数的整数：");
  5.     scanf("%d", &number);
  6.  
  7.     // 提取各个位上的数字
  8.     int number_wan = number / 10000; // 提取万位
  9.     int number_qian = (number % 10000) / 1000; // 提取千位
  10.     int number_bai = (number % 10000 % 1000) / 100; // 提取百位
  11.     int number_shi = (number % 10000 % 1000 % 100) / 10; // 提取十位
  12.     int number_ge = number % 10000 % 1000 % 100 % 10; // 提取个位
  13.  
  14.     // 根据不同的位数情况逆序输出
  15.     if (number_wan == 0) {
  16.         printf("%d %d %d %d %d\n", number_ge, number_shi, number_bai, number_qian, number_wan);
  17.     } else if (number_wan != 0 && number_qian == 0) {
  18.         printf("%d %d %d %d\n", number_ge, number_shi, number_bai, number_wan);
  19.     } else if (number_wan != 0 && number_qian != 0 && number_bai == 0) {
  20.         printf("%d %d %d\n", number_ge, number_shi, number_wan);
  21.     } else if (number_wan != 0 && number_qian != 0 && number_bai != 0 && number_shi == 0) {
  22.         printf("%d %d\n", number_ge, number_wan);
  23.     } else if (number_wan != 0 && number_qian != 0 && number_bai != 0 && number_shi != 0 && number_ge == 0) {
  24.         printf("%d\n", number_wan);
  25.     } else {
  26.         printf("%d %d %d %d %d\n", number_ge, number_shi, number_bai, number_qian, number_wan);
  27.     }
  28.  
  29.     return 0;
  30. }
Success #stdin #stdout 0s 5280KB
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请输入一个不多于五位数的整数：1 0 0 0 0
https://ideone.com/XkxAZX
language:
C (gcc 8.3)
created:
3 days ago
visibility:
public

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