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  1. let rec perm (ls :'a list) (n :int) :'a list list =
  2.     if n = 0 then [[]]
  3.         else
  4.           [for x in ls do
  5.             for xs in perm (ls |> List.filter (fun a -> a<>x)) (n-1) do
  6.               yield x::xs]
  7.  
  8. for [a;b;c;d;e] in perm [1 ..15] 5 do
  9.     if [a; b; c; d; e
  10.         a+b; b+c; c+d; d+e; e+a
  11.         a+b+c; b+c+d; c+d+e; d+e+a; e+a+b
  12.         a+b+c+d; b+c+d+e; c+d+e+a; d+e+a+b; e+a+b+c
  13.         a+b+c+d+e] |> List.sort = [1..21] then
  14.             printfn "%A" (a,b,c,d,e)
Success #stdin #stdout 1.36s 151040KB
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stdin
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Standard input is empty
stdout
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(1, 3, 10, 2, 5)
(1, 5, 2, 10, 3)
(2, 5, 1, 3, 10)
(2, 10, 3, 1, 5)
(3, 1, 5, 2, 10)
(3, 10, 2, 5, 1)
(5, 1, 3, 10, 2)
(5, 2, 10, 3, 1)
(10, 2, 5, 1, 3)
(10, 3, 1, 5, 2)
https://ideone.com/WXgnP1
language:
F# (mono 4.1)
created:
6 years ago
visibility:
public

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