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  1. #include <cstdio>
  2. #include <cmath>
  3. int main() {
  4. long long t,n;
  5. scanf("%lld",&t);
  6. for(long long i=1;i<=t;i++){
  7. scanf("%lld",&n);
  8. long long squareroot = (long)(sqrt (n));
  9. if((squareroot * squareroot) == n){
  10. printf("%s%lld%s\n","Case ",i,": Yes");}
  11. else {printf("%s%lld%s\n","Case ",i,": No");}}}
  12.  
  13.  
  14.  
Success #stdin #stdout 0s 2688KB
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Case 1: No
Case 2: Yes
https://ideone.com/WSwgS9
language:
C++ 4.3.2 (gcc-4.3.2)
created:
9 years ago
visibility:
public

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