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  1. def implication(a, b):
  2.     return not a or b
  3.  
  4. # полная таблица истинности (как в вашем коде)
  5. table = []
  6. for x in (0, 1):
  7.     for y in (0, 1):
  8.         for z in (0, 1):
  9.             for w in (0, 1):
  10.                 f1 = int(implication(w, y) == implication(z, x))
  11.                 f2 = int(implication(w, y) and (not x) == z)
  12.                 table.append({'x': x, 'y': y, 'z': z, 'w': w, 'f1': f1, 'f2': f2})
  13.  
  14. # фрагмент из задания ('?' - пусто)
  15. rows = [
  16.     [0, '?', 0, 0, 0, 1],
  17.     [0, 0, 0, '?', 0, '?'],
  18.     [0, 1, 1, '?', '?', 0],
  19. ]
  20.  
  21. # перебираем, какая переменная в каком столбце
  22. for a in 'xyzw':
  23.     for b in 'xyzw':
  24.         for c in 'xyzw':
  25.             for d in 'xyzw':
  26.                 if len({a, b, c, d}) < 4:
  27.                     continue
  28.                 cols = [a, b, c, d, 'f1', 'f2']
  29.                 ok = True
  30.                 for row in rows:
  31.                     found = False
  32.                     for t in table:
  33.                         match = True
  34.                         for i in range(6):
  35.                             if row[i] != '?' and row[i] != t[cols[i]]:
  36.                                 match = False
  37.                         if match:
  38.                             found = True
  39.                     if not found:
  40.                         ok = False
  41.                 if ok:
  42.                     print(a + b + c + d)
Success #stdin #stdout 0.09s 14212KB
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yzxw
https://ideone.com/VKJRoX
language:
Python 3 (python  3.12)
created:
35 minutes ago
visibility:
public

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