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  1. #include <stdlib.h>
  2. #include <stdio.h>
  3. #include <math.h>
  4.  
  5. void forloop(int firstNum,int ratio,int repeats);
  6. int main(void)
  7. { 
  8.     int firstNum = 0;
  9.     int ratio = 0;
  10.     int repeats = 0;
  11.     printf("First number of the series: ");
  12.     scanf("%d", &firstNum);
  13.     printf("the ratio of the series: ");
  14.     scanf("%d", &ratio);
  15.     printf("the amount of numbers to display is ");
  16.     scanf("%d", &repeats);
  17.     forloop(firstNum,ratio,repeats);
  18. }
  19.  
  20. void forloop(int firstNum,int ratio,int repeats)
  21. {
  22.     int i = 0;
  23.     for (i=1; i!=repeats+1;i++)
  24.     {
  25.         printf("%d ", firstNum*(pow( ratio, i)));
  26.     }
  27. }
  28.  
Compilation error #stdin compilation error #stdout 0s 0KB
comments (?)
stdin
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3 2 10
compilation info 
prog.c: In function ‘forloop’:
prog.c:25:18: error: format ‘%d’ expects argument of type ‘int’, but argument 2 has type ‘double’ [-Werror=format=]
         printf("%d ", firstNum*(pow( ratio, i)));
                  ^
cc1: all warnings being treated as errors
stdout
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Standard output is empty
https://ideone.com/VAdUbZ
language:
C99 (gcc 8.3)
created:
6 years ago
visibility:
public

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