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#include <iostream>
#include <map>
#include <utility>
 
using namespace std;
 
struct one {
    void foo(const int) {}
    void bar() {}
};
 
struct two {
    void foo(const int) {}
};
 
struct three {
    void foo(const int) {}
    void bar() {}
};
 
struct owner {
    map<int, one> ones;
    map<int, two> twos;
    map<int, three> threes;
 
    template <typename T, typename Func>
    void callFunc(T& param, const Func& func) {
        func(param);
    }
 
    template <typename T>
    void findObject(int key, const T& func) {
        if(ones.count(key) != 0U) {
            callFunc(ones[key], func);
        } else if(twos.count(key) != 0U) {
            callFunc(twos[key], func);
        } else {
            callFunc(threes[key], func);
        }
    }
 
    void foo(const int key, const int param) { findObject(key, [&](auto& value) { value.foo(param); } ); }
    void bar(const int key) { findObject(key, [&](auto& value) { value.bar(); } ); }
};
int main() {
	owner myOwner;
 
	myOwner.ones.insert(make_pair(0, one()));
	myOwner.twos.insert(make_pair(1, two()));
	myOwner.threes.insert(make_pair(2, three()));
 
	myOwner.foo(2, 1);
}

prog.cpp: In instantiation of ‘owner::bar(int)::<lambda(auto:2&)> [with auto:2 = two]’:
prog.cpp:28:13:   required from ‘void owner::callFunc(T&, const Func&) [with T = two; Func = owner::bar(int)::<lambda(auto:2&)>]’
prog.cpp:36:13:   required from ‘void owner::findObject(int, const T&) [with T = owner::bar(int)::<lambda(auto:2&)>]’
prog.cpp:43:81:   required from here
prog.cpp:43:72: error: ‘struct two’ has no member named ‘bar’
     void bar(const int key) { findObject(key, [&](auto& value) { value.bar(); } ); }
                                                                  ~~~~~~^~~

Standard output is empty