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  1. awk -F , -v RS='(' 'NF>=5 { x=$3; gsub(/\"/, "", x); print x}' <<\:
  2. +COPS: (1,"Orange F","Orange","20801",2),(1,"Swisscom","Swisscom","22801",7),(1,"Swisscom","Swisscom","22801",2),(1,"Salt","Salt","22803",2),(1,"Sunrise","Sunrise","22802",2),(1,"Sunrise","Sunrise","22802",7),(1,"Sunrise","Sunrise","22802",0),(2,"Salt","Salt","22803",7),(1,"Free","Free","20815",2),(1,"F SFR","SFR","20810",7),(1,"F-Bouygues Telecom","BYTEL","20820",7),,(0-4),(0-2)
  3. :
Success #stdin #stdout 0s 4320KB
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Standard input is empty
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Orange
Swisscom
Swisscom
Salt
Sunrise
Sunrise
Sunrise
Salt
Free
SFR
BYTEL
https://ideone.com/UvEXXH
https://stackoverflow.com/questions/60282365/bash-regex-that-returns-short-alphanumeric-operator-name-from-at-command-atcops
language:
Bash (bash 5.0.3)
created:
4 years ago
visibility:
public

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